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Fix & make linux conditionals uniform (#4278)

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The source used a hodge-podge of different combinations of different
macros to check for linux: 'linux', '__linux', '__linux__'.

As '__linux__' is standard (Posix), and the others are not, the source
now uniformly uses __linux__. If either linux or __linux are defined,
it is made sure that __linux__ is defined as well.
This commit is contained in:
Rogier-5
2016-07-04 21:00:57 +02:00
committed by est31
parent f649147080
commit 1dfd977ec4
5 changed files with 14 additions and 10 deletions
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2
src/intlGUIEditBox.cpp
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@@ -271,7 +271,7 @@ bool intlGUIEditBox::OnEvent(const SEvent& event)
break;
case EET_KEY_INPUT_EVENT:
{
#if (defined(linux) || defined(__linux) || defined(__FreeBSD__))
#if (defined(__linux__) || defined(__FreeBSD__))
// ################################################################
// ValkaTR:
// This part is the difference from the original intlGUIEditBox