chest_lid_close: don't replace a node if it's not the expected open chest

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fluxionary 2023-08-11 04:00:22 -07:00 committed by GitHub
parent 960aff2f63
commit 83c10f59e1
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@ -38,16 +38,23 @@ function default.chest.chest_lid_close(pn)
default.chest.open_chests[pn] = nil default.chest.open_chests[pn] = nil
for k, v in pairs(default.chest.open_chests) do for k, v in pairs(default.chest.open_chests) do
if v.pos.x == pos.x and v.pos.y == pos.y and v.pos.z == pos.z then if vector.equals(v.pos, pos) then
-- another player is also looking at the chest
return true return true
end end
end end
local node = minetest.get_node(pos) local node = minetest.get_node(pos)
minetest.after(0.2, minetest.swap_node, pos, { name = swap, minetest.after(0.2, function()
param2 = node.param2 }) local current_node = minetest.get_node(pos)
if current_node.name ~= swap .. "_open" then
-- the chest has already been replaced, don't try to replace what's there.
return
end
minetest.swap_node(pos, {name = swap, param2 = node.param2})
minetest.sound_play(sound, {gain = 0.3, pos = pos, minetest.sound_play(sound, {gain = 0.3, pos = pos,
max_hear_distance = 10}, true) max_hear_distance = 10}, true)
end)
end end
default.chest.open_chests = {} default.chest.open_chests = {}