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Make sorting tubes not drop elements if all outputs filtering for a specific element are filled.

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Send them to some other open (empty) port instead.
This commit is contained in:
est31 2015-02-03 23:12:10 +01:00
parent 50b417ce13
commit 8e9affc841
1 changed files with 23 additions and 16 deletions
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39
sorting_tubes.lua
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@ -52,22 +52,29 @@ if pipeworks.enable_mese_tube then
local inv = meta:get_inventory()
local name = stack:get_name()
for i, vect in ipairs(pipeworks.meseadjlist) do
if meta:get_int("l"..i.."s") == 1 then
local invname = "line"..i
local is_empty = true
for _, st in ipairs(inv:get_list(invname)) do
if not st:is_empty() then
is_empty = false
if st:get_name() == name then
foundn = foundn + 1
found[foundn] = vect
end
end
end
if is_empty then
tbln = tbln + 1
tbl[tbln] = vect
end
local npos = vector.add(pos, vect)
local node = minetest.get_node(npos)
local reg_node = minetest.registered_nodes[node.name]
if meta:get_int("l"..i.."s") == 1 and reg_node then
local tube_def = reg_node.tube
if not tube_def or not tube_def.can_insert or
tube_def.can_insert(npos, node, stack, vect) then
local invname = "line"..i
local is_empty = true
for _, st in ipairs(inv:get_list(invname)) do
if not st:is_empty() then
is_empty = false
if st:get_name() == name then
foundn = foundn + 1
found[foundn] = vect
end
end
end
if is_empty then
tbln = tbln + 1
tbl[tbln] = vect
end
end
end
end
return (foundn > 0) and found or tbl